/*  hts_time_funcs.h -- Implementations of non-standard time functions

    Copyright (C) 2022 Genome Research Ltd.

    Author: Rob Davies <rmd@sanger.ac.uk>

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THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
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DEALINGS IN THE SOFTWARE.  */

/*
  This mainly exists because timegm() is not a standard function, and so
  Cannot be used in portable code.  Unfortunately the standard one (mktime)
  always takes the local timezone into accout so doing a UTC conversion
  with it involves changing the TZ environment variable, which is rather
  messy and not likely to go well with threaded code.

  The code here is a much simplified version of the BSD timegm() implementation.
  It currently rejects dates before 1970, avoiding problems with -ve time_t.
  It also works strictly in UTC, so doesn't have to worry about tm_isdst
  which makes the calculation much easier.

  Some of this is derived from BSD sources, for example
  https://github.com/NetBSD/src/blob/trunk/lib/libc/time/localtime.c
  which state:

  ** This file is in the public domain, so clarified as of
  ** 1996-06-05 by Arthur David Olson.

  Non-derived code is copyright as above.
*/

#include <stdint.h>
#include <limits.h>
#include <errno.h>
#include <time.h>

static inline int hts_time_normalise(int *tens, int *units, int base) {
    if (*units < 0 || *units >= base) {
        int delta = *units >= 0 ? *units / base : (-1 - (-1 - *units) / base);
        int64_t tmp = (int64_t) (*tens) + delta;
        if (tmp < INT_MIN || tmp > INT_MAX) return 1;
        *tens = tmp;
        *units -= delta * base;
    }
    return 0;
}

static inline int hts_year_is_leap(int64_t year) {
    return ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);
}

// Number of leap years to start of year
// Only works for year >= 1.
static inline int64_t hts_leaps_to_year_start(int64_t year) {
    --year;
    return year / 4 - year / 100 + year / 400;
}

static inline int hts_time_normalise_tm(struct tm *t)
{
    const int days_per_mon[2][12] = {
        { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 },
        { 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }
    };
    const int year_days[2] = { 365, 366 };
    int overflow = 0;
    int64_t year;

    if (t->tm_sec > 62) {
        overflow |= hts_time_normalise(&t->tm_min, &t->tm_sec, 60);
    }
    overflow |= hts_time_normalise(&t->tm_hour, &t->tm_min,  60);
    overflow |= hts_time_normalise(&t->tm_mday, &t->tm_hour, 24);
    overflow |= hts_time_normalise(&t->tm_year, &t->tm_mon,  12);
    if (overflow)
        return 1;

    year = (int64_t) t->tm_year + 1900LL;
    while (t->tm_mday <= 0) {
        --year;
        t->tm_mday += year_days[hts_year_is_leap(year + (1 < t->tm_mon))];
    }
    while (t->tm_mday > 366) {
        t->tm_mday -= year_days[hts_year_is_leap(year + (1 < t->tm_mon))];
        ++year;
    }
    for (;;) {
        int mdays = days_per_mon[hts_year_is_leap(year)][t->tm_mon];
        if (t->tm_mday <= mdays)
            break;
        t->tm_mday -= mdays;
        t->tm_mon++;
        if (t->tm_mon >= 12) {
            year++;
            t->tm_mon = 0;
        }
    }
    year -= 1900;
    if (year != t->tm_year) {
        if (year < INT_MIN || year > INT_MAX)
            return 1;
        t->tm_year = year;
    }
    return 0;
}

/**
 *  Convert broken-down time to an equivalent time_t value
 *  @param target  Target broken-down time structure
 *  @return Equivalent time_t value on success; -1 on failure
 *
 *  This function first normalises the time in @p target so that the
 *  structure members are in the valid range.  It then calculates the
 *  number of seconds (ignoring leap seconds) between midnight Jan 1st 1970
 *  and the target date.
 *
 *  If @p target is outside the range that can be represented in a time_t,
 *  or tm_year is less than 70 (which would return a negative value) then
 *  it returns -1 and sets errno to EOVERFLOW.
 */

static inline time_t hts_time_gm(struct tm *target)
{
    int month_start[2][12] = {
        { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334 },
        { 0, 31, 60, 91, 121, 152, 182, 213, 244, 274, 305, 335 }
    };
    int years_from_epoch, leaps, days;
    int64_t secs;

    if (hts_time_normalise_tm(target) != 0)
        goto overflow;

    if (target->tm_year < 70)
        goto overflow;

    years_from_epoch = target->tm_year - 70;
    leaps = (hts_leaps_to_year_start(target->tm_year + 1900)
        - hts_leaps_to_year_start(1970));
    days = ((365 * (years_from_epoch - leaps) + 366 * leaps)
        + month_start[hts_year_is_leap(target->tm_year + 1900)][target->tm_mon]
        + target->tm_mday - 1);
    secs = ((int64_t) days * 86400LL
        + target->tm_hour * 3600
        + target->tm_min * 60
        + target->tm_sec);
    if (sizeof(time_t) < 8 && secs > INT_MAX)
        goto overflow;

    return (time_t) secs;

 overflow:
    errno = EOVERFLOW;
    return (time_t) -1;
}