/* * BioJava development code * * This code may be freely distributed and modified under the * terms of the GNU Lesser General Public Licence. This should * be distributed with the code. If you do not have a copy, * see: * * http://www.gnu.org/copyleft/lesser.html * * Copyright for this code is held jointly by the individual * authors. These should be listed in @author doc comments. * * For more information on the BioJava project and its aims, * or to join the biojava-l mailing list, visit the home page * at: * * http://www.biojava.org/ * */ package org.biojava.utils.math; import org.biojava.bio.BioException; /** * solves y = f(x) = 0 by binary search. * Only really suitable for monotonic functions as * the method will check that the initial values * lie on opposite sides of the X=0 axis. * * @author David Huen */ public class BinarySearch { /** * method that will attempt solving the equation. * * @param min lower bound of search space. * @param max upper bound of search space. * @param tolerance change in x required to continue iteration. * @param obj the class of ComputeObject class representing the equation to be solved. */ public static double solve(double min, double max, double tolerance, ComputeObject obj) throws BioException { // compute initial values double x1 = min; double y1 = obj.compute(min); double x2 = max; double y2 = obj.compute(max); // validate that function standas some chance of monotonicity if ((y1 < 0.0) && (y2 < 0.0)) throw new BioException("Illegal initial range limits."); if ((y1 > 0.0) && (y2 > 0.0)) throw new BioException("Illegal initial range limits."); // iterate while (Math.abs(x1 - x2) > tolerance) { // compute a value midway within the current interval double newX = 0.5 * (x1 + x2); double newY = obj.compute(newX); // determine new interval if (newY >= 0.0) { if (y1 >= 0.0) { y1 = newY; x1 = newX; } else { y2 = newY; x2 = newX; } } else if (newY < 0.0) { if (y1 >= 0.0) { y2 = newY; x2 = newX; } else { y1 = newY; x1 = newX; } } } // converged: return midpoint of interval return 0.5 * (x1 + x2); } }