// Boost.Geometry // Copyright (c) 2017 Oracle and/or its affiliates. // Contributed and/or modified by Vissarion Fysikopoulos, on behalf of Oracle // Use, modification and distribution is subject to the Boost Software License, // Version 1.0. (See accompanying file LICENSE_1_0.txt or copy at // http://www.boost.org/LICENSE_1_0.txt) #ifndef BOOST_GEOMETRY_FORMULAS_ELLIPTIC_ARC_LENGTH_HPP #define BOOST_GEOMETRY_FORMULAS_ELLIPTIC_ARC_LENGTH_HPP #include #include #include #include #include #include #include namespace boost { namespace geometry { namespace formula { /*! \brief Compute the arc length of an ellipse. */ template class elliptic_arc_length { public : struct result { result() : distance(0) , meridian(false) {} CT distance; bool meridian; }; template static result apply(T lon1, T lat1, T lon2, T lat2, Spheroid const& spheroid) { result res; CT c0 = 0; CT pi = math::pi(); CT half_pi = pi/CT(2); CT diff = geometry::math::longitude_distance_signed(lon1, lon2); if (lat1 > lat2) { std::swap(lat1, lat2); } if ( math::equals(diff, c0) || (math::equals(lat2, half_pi) && math::equals(lat1, -half_pi)) ) { // single meridian not crossing pole res.distance = apply(lat2, spheroid) - apply(lat1, spheroid); res.meridian = true; } if (math::equals(math::abs(diff), pi)) { // meridian crosses pole CT lat_sign = 1; if (lat1+lat2 < c0) { lat_sign = CT(-1); } res.distance = math::abs(lat_sign * CT(2) * apply(half_pi, spheroid) - apply(lat1, spheroid) - apply(lat2, spheroid)); res.meridian = true; } return res; } // Distance computation on meridians using series approximations // to elliptic integrals. Formula to compute distance from lattitude 0 to lat // https://en.wikipedia.org/wiki/Meridian_arc // latitudes are assumed to be in radians and in [-pi/2,pi/2] template static CT apply(T lat, Spheroid const& spheroid) { CT const a = get_radius<0>(spheroid); CT const f = formula::flattening(spheroid); CT n = f / (CT(2) - f); CT M = a/(1+n); CT C0 = 1; if (Order == 0) { return M * C0 * lat; } CT C2 = -1.5 * n; if (Order == 1) { return M * (C0 * lat + C2 * sin(2*lat)); } CT n2 = n * n; C0 += .25 * n2; CT C4 = 0.9375 * n2; if (Order == 2) { return M * (C0 * lat + C2 * sin(2*lat) + C4 * sin(4*lat)); } CT n3 = n2 * n; C2 += 0.1875 * n3; CT C6 = -0.729166667 * n3; if (Order == 3) { return M * (C0 * lat + C2 * sin(2*lat) + C4 * sin(4*lat) + C6 * sin(6*lat)); } CT n4 = n2 * n2; C4 -= 0.234375 * n4; CT C8 = 0.615234375 * n4; if (Order == 4) { return M * (C0 * lat + C2 * sin(2*lat) + C4 * sin(4*lat) + C6 * sin(6*lat) + C8 * sin(8*lat)); } CT n5 = n4 * n; C6 += 0.227864583 * n5; CT C10 = -0.54140625 * n5; // Order 5 or higher return M * (C0 * lat + C2 * sin(2*lat) + C4 * sin(4*lat) + C6 * sin(6*lat) + C8 * sin(8*lat) + C10 * sin(10*lat)); } // Iterative method to elliptic arc length based on // http://www.codeguru.com/cpp/cpp/algorithms/article.php/c5115/ // Geographic-Distance-and-Azimuth-Calculations.htm // latitudes are assumed to be in radians and in [-pi/2,pi/2] template CT interative_method(T1 lat1, T2 lat2, Spheroid const& spheroid) { CT result = 0; CT const zero = 0; CT const one = 1; CT const c1 = 2; CT const c2 = 0.5; CT const c3 = 4000; CT const a = get_radius<0>(spheroid); CT const f = formula::flattening(spheroid); // how many steps to use CT lat1_deg = lat1 * geometry::math::r2d(); CT lat2_deg = lat2 * geometry::math::r2d(); int steps = c1 + (c2 + (lat2_deg > lat1_deg) ? CT(lat2_deg - lat1_deg) : CT(lat1_deg - lat2_deg)); steps = (steps > c3) ? c3 : steps; //std::cout << "Steps=" << steps << std::endl; CT snLat1 = sin(lat1); CT snLat2 = sin(lat2); CT twoF = 2 * f - f * f; // limits of integration CT x1 = a * cos(lat1) / sqrt(1 - twoF * snLat1 * snLat1); CT x2 = a * cos(lat2) / sqrt(1 - twoF * snLat2 * snLat2); CT dx = (x2 - x1) / (steps - one); CT x, y1, y2, dy, dydx; CT adx = (dx < zero) ? -dx : dx; // absolute value of dx CT a2 = a * a; CT oneF = 1 - f; // now loop through each step adding up all the little // hypotenuses for (int i = 0; i < (steps - 1); i++){ x = x1 + dx * i; dydx = ((a * oneF * sqrt((one - ((x+dx)*(x+dx))/a2))) - (a * oneF * sqrt((one - (x*x)/a2)))) / dx; result += adx * sqrt(one + dydx*dydx); } return result; } }; }}} // namespace boost::geometry::formula #endif // BOOST_GEOMETRY_FORMULAS_ELLIPTIC_ARC_LENGTH_HPP